m^2-4m-76=-6

Solution for m^2-4m-76=-6 equation:

m^2-4m-76=-6

We move all terms to the left:

m^2-4m-76-(-6)=0

We add all the numbers together, and all the variables

m^2-4m-70=0

a = 1; b = -4; c = -70;
Δ = b2-4ac
Δ = -42-4·1·(-70)
Δ = 296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{296}=\sqrt{4*74}=\sqrt{4}*\sqrt{74}=2\sqrt{74}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{74}}{2*1}=\frac{4-2\sqrt{74}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{74}}{2*1}=\frac{4+2\sqrt{74}}{2}
$